Match List-I with List-II
|
List-I Common Name |
List-II IUPAC Name |
|
(A) Diisopropyl ketone |
(I) 2-Methylpropanal |
|
(B) Isobutyraldehyde |
(II) Prop-2-enal |
|
(C) Phthaldehyde |
(III) 2,4-Dimethylpentan-3-one |
|
(D) Acrolein |
(IV) Benzene-1,2-dicarbaldehyde |
Choose the correct answer from the options given below:
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → (A)-(III), (B)-(I), (C)-(IV), (D)-(II)
To turn a common name into an IUPAC name, first write the structure. Then take the longest chain containing the carbonyl carbon, number it so that the carbonyl carbon gets the lowest number (in aldehydes the CHO carbon is C-1), and add the suffix -al for aldehydes or -one for ketones. When a CHO group is attached to a ring, the suffix -carbaldehyde is used.
(A) Diisopropyl ketone — This matches (III) 2,4-Dimethylpentan-3-one. Two isopropyl groups on a C=O give \( \ce{(CH3)2CH-CO-CH(CH3)2} \): a five-carbon chain with the C=O at C-3 and methyl groups at C-2 and C-4.
(B) Isobutyraldehyde — This matches (I) 2-Methylpropanal. Its structure is \( \ce{(CH3)2CH-CHO} \): a three-carbon chain with the CHO carbon as C-1 and a methyl group on C-2.
(C) Phthaldehyde — This matches (IV) Benzene-1,2-dicarbaldehyde. It is benzene with two CHO groups on adjacent carbon atoms, \( \ce{C6H4(CHO)2} \) (ortho), named with the suffix -dicarbaldehyde.
(D) Acrolein — This matches (II) Prop-2-enal. Its structure is \( \ce{CH2=CH-CHO} \): three carbons, CHO as C-1 and the double bond starting at C-2.
Shortcut: Isobutyraldehyde is a three-carbon aldehyde with a methyl branch, so (B)-(I); this pair appears only in Option (2).
NCERT (2026-27 edition):
IUPAC Names – …
