3.65 g of HCl is dissolved in 16.2 g of water. The mole fraction of HCl in the resulting solution is:

0.1

To calculate the mole fraction of HCl in the resulting solution, we need to determine the moles of HCl and moles of water first.

Given:
Mass of HCl = 3.65 g
Molar mass of HCl = 36.46 g/mol

Moles of HCl = \(\frac{{\text{{Mass of HCl}}}}{{\text{{Molar mass of HCl}}}} = \frac{{3.65 \, \text{g}}}{{36.46 \, \text{g/mol}}} = 0.1 \, \text{mol}\)

Mass of water = 16.2 g
Molar mass of water (H₂O) = 18.02 g/mol

Moles of water = \(\frac{{\text{{Mass of water}}}}{{\text{{Molar mass of water}}}} = \frac{{16.2 \, \text{g}}}{{18.02 \, \text{g/mol}}} = 0.899 \, \text{mol}\)

Now, we can calculate the mole fraction of HCl using the formula:

Mole fraction of HCl = \(\frac{{\text{{Moles of HCl}}}}{{\text{{Moles of HCl}} + \text{{Moles of water}}}} = \frac{{0.1 \, \text{mol}}}{{0.1 \, \text{mol} + 0.899 \, \text{mol}}} \approx 0.1001\)

Rounded to three decimal places, the mole fraction of HCl in the resulting solution is approximately 0.100.

Therefore, the closest option to the calculated value is (d) 0.1.