Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Differential Equations

Question:

The differential equation of all circles which pass through the origin and whose centre is on y-axis, is

Options:

a homogeneous differential equation

a differential equation of order 1 and degree 2

a differential equation in variable separable form

a differential equation reducible to variable separable form

Correct Answer:

a homogeneous differential equation

Explanation:

The differential equation representing the given family of circle is

$\left(x^2-y^2\right) \frac{d y}{d x}=2 x y$

or, $\frac{d y}{d x}=\frac{2 x y}{x^2-y^2}$

Clearly, it is a homogeneous differential equation.