The molar specific heats of an ideal gas at constant pressure and volume are denoted by Cp and Cv respectively. If \(\gamma=\frac{C_P}{C_V}\) and R is the universal gas constant, then Cv is equal to:
Answer & explanation
Correct answer: option 3
\(C_P - C_V = R\) -------(1)
and \(\frac{C_P}{C_V} = \gamma \)
Dividing equation (1) by $C_V$,
$\frac{C_P}{C_V}$ - $\frac{C_V}{C_V}$ = $\frac{R}{C_V}$
\(\gamma\) - 1 = $\frac{R}{C_V}$
$C_V = \frac{R}{\gamma - 1}$