Practicing Success
The molar specific heats of an ideal gas at constant pressure and volume are denoted by Cp and Cv respectively. If \(\gamma=\frac{C_P}{C_V}\) and R is the universal gas constant, then Cv is equal to:
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\(\gamma R\) \(\frac{1+\gamma}{1-\gamma}\) \(\frac{R}{\gamma - 1}\) \(\frac{\gamma - 1}{R}\) |
\(\frac{R}{\gamma - 1}\) |
\(C_P - C_V = R\) -------(1) and \(\frac{C_P}{C_V} = \gamma \) Dividing equation (1) by $C_V$, $\frac{C_P}{C_V}$ - $\frac{C_V}{C_V}$ = $\frac{R}{C_V}$ \(\gamma\) - 1 = $\frac{R}{C_V}$ $C_V = \frac{R}{\gamma - 1}$ |