Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Kinetic Theory

Question:

The molar specific heats of an ideal gas at constant pressure and volume are denoted by Cp and Cv respectively. If \(\gamma=\frac{C_P}{C_V}\) and R is the universal gas constant, then Cv is equal to:

 

Options:

\(\gamma R\)

\(\frac{1+\gamma}{1-\gamma}\)

\(\frac{R}{\gamma - 1}\)

\(\frac{\gamma - 1}{R}\)

Correct Answer:

\(\frac{R}{\gamma - 1}\)

Explanation:

\(C_P - C_V = R\) -------(1)

and \(\frac{C_P}{C_V} = \gamma \)

Dividing equation (1) by $C_V$, 

$\frac{C_P}{C_V}$ - $\frac{C_V}{C_V}$ = $\frac{R}{C_V}$

\(\gamma\) - 1 =  $\frac{R}{C_V}$

$C_V = \frac{R}{\gamma - 1}$