In a $\triangle ABC$, the bisector of $\angle B$ and $\angle C$ meet at O in the triangle. If $\angle BOC = 134^\circ$, then the measure of $\angle A$ is:

88°

As, BO and CO are angle bisectors of \(\angle\)B and \(\angle\)C

\(\angle\)BOC = 90 + \(\frac{A}{2}\)

= 134 = 90 + \(\frac{A}{2}\)

= \(\angle\)A = 2 x 44 = 88

= \(\angle\)A is \({88}^\circ\).