Practicing Success
Practicing Success
CUET Preparation Today
A short bar magnet of magnetic moment $m=0.45 J/T$ is placed in a uniform magnetic field of 0.22T. If the bar is free to rotate in the plane of the field, what is the potential energy of the magnet in stable and unstable equilibrium respectively? |
$-9.8×10^{-2} J$ (Unstable); Zero (Stable) Zero (Unstable); $9.8×10^{-2} J$, (Stable) $-9.8×10^{-2} J$ (Unstable); $9.8×10^{-2} J$, (Stable) $9.8×10^{-2} J$ (Unstable); $-9.8×10^{-2} J$, (Stable) |
$9.8×10^{-2} J$ (Unstable); $-9.8×10^{-2} J$, (Stable) |
The correct answer is Option (4) → $9.8×10^{-2} J$ (Unstable); $-9.8×10^{-2} J$, (Stable) |
