An ionic atom equivalent to hydrogen atom has wavelength equal to 1/4 of the wavelengths of hydrogen lines. The ion will be
Answer & explanation
Correct answer: option 1
$\bar{v} \propto \frac{1}{\lambda} \propto Z^2 \Rightarrow \lambda Z^2$ = constant
$\Rightarrow \lambda=\frac{\lambda}{4} Z^2 \Rightarrow Z=2$