Match List I with List II

Choose the correct answer from the option given below:

A-iii, B-i, C-iv, D-ii

The correct answer is option 1. A-iii, B-i, C-iv, D-ii.

In the given question, we are provided with electronic configurations for four different elements: Silicon (Si), Vanadium (V), Copper (Cu), and Selenium (Se). We need to match each element with its corresponding electronic configuration.

Let's break down the electronic configurations and match them accordingly:

A. Silicon (Si) has electronic configuration \(1s^2 2s^2 2p^6 3s^2 3p^2\) (iii).

This configuration represents Silicon, which has 14 electrons. The electronic configuration fills up the 1s, 2s, 2p, and 3s orbitals completely, with two electrons in each orbital, and then adds two more electrons to the 3p orbital.

B. Vanadium (V) has electronic configuration \(1s^2 2s^2 2p^6 3s^2 3p^6 3d^3 4s^2\) (i).

This configuration represents Vanadium, which has 23 electrons. The electronic configuration fills up the 1s, 2s, 2p, 3s, 3p, and 4s orbitals completely, with two electrons in each orbital, and then adds three electrons to the 3d orbital.

C. Copper (Cu) has electronic configuration \(1s^2 2s^2 2p^6 3s^2 3p^6 3d^{10} 4s^1\) (iv).

This configuration represents Copper, which has 29 electrons. The electronic configuration fills up the 1s, 2s, 2p, 3s, 3p, 3d orbitals completely, with two electrons in each orbital, and then adds one electron to the 4s orbital.

D. Selenium (Se) has electronic configuration \(1s^2 2s^2 2p^6 3s^2 3p^6 3d^{10} 4s^2 4p^4\) (ii).

This configuration represents Selenium, which has 34 electrons. The electronic configuration fills up the 1s, 2s, 2p, 3s, 3p, 3d, and 4s orbitals completely, with two electrons in each orbital, and then adds four electrons to the 4p orbital.