In $\triangle ABC, \angle A = 68^\circ$. If is the incentre of the triangle, then measure of $\angle BIC$ is:
Answer & explanation
Correct answer: option 1
According to the concept,
\(\angle\)BIC = 90 + \(\frac{1}{2}\) x \(\angle\)BAC
= \(\angle\)BIC = 90 + \(\frac{1}{2}\) x 68
= \(\angle\)BIC = 90 + 34
= \(\angle\)BIC = \({124}^\circ\)
Therefore, \(\angle\)BIC is \({124}^\circ\).