Practicing Success
Given that T stands for time period and l stands for length of simple pendulum. If g is the acceleration due to gravity, then which of the following statements about T2 = 4π l/g correct ? |
It is correct both dimensionally as well as numerically It is correct neither dimensionally nor numerically It is dimensionally correct but not numerically It is numerically correct but not dimensionally |
It is dimensionally correct but not numerically |
Time period of a simple pendulum : T = \(2 \pi \sqrt{\frac{l}{g}}\) T2 = \(4 \pi^2 \frac{l}{g}\) So, the given relation is correct dimensionally but NOT numerically. |