Practicing Success
Practicing Success
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$I=\int \frac{\left(10 x^9+10^x \log _e 10\right)}{\left(x^{10}+10^x\right)} d x$ is equal to : |
$10^x+x^{10}+c$ $10^x-x^{10}+c$ $10^x+x^{10}+c$ $\log _e\left(10^x+x^{10}\right)+c$ |
$\log _e\left(10^x+x^{10}\right)+c$ |
If $10^x+x^{10}=p \Rightarrow\left(10^x \ln 10+10 x^9\right) d x=d p ; I=\ln \left(x^{10}+10^x\right)+c$ Hence (4) is the correct answer. |
