A satellite goes along an elliptical path around earth. The rate of change of arc length ‘a’ swept by the satellite is proportional to:
Answer & explanation
Correct answer: option 4
$\frac{dA}{dt}=\frac{1}{2} r^2 \omega$ = constant k = k
$\Rightarrow \frac{1}{2} r(r \omega)$ = k ⇒ vr = 2k
⇒ v ∝ (1/r)