CUET Preparation Today
A heating element is marked 210 V, 630 W. The resistance of the element would be |
50 Ω 60 Ω 40 Ω 70 Ω |
70 Ω |
The correct answer is Option (4) → 70 Ω Power is given by: $P = \frac{V^2}{R}$ Therefore, $R = \frac{V^2}{P} = \frac{210^2}{630}$ $R = \frac{44100}{630} = 70 \ \Omega$ Resistance of the element = 70 Ω |
