A heating element is marked 210 V, 630 W. The resistance of the element would be
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → 70 Ω
Power is given by:
$P = \frac{V^2}{R}$
Therefore,
$R = \frac{V^2}{P} = \frac{210^2}{630}$
$R = \frac{44100}{630} = 70 \ \Omega$
Resistance of the element = 70 Ω