Read the passage carefully and answer the Questions. The decomposition of $N_2O_5 (g)$ is given as $N_2Os (g) → 2NO_2(g) +\frac{1}{2}O_2(g)$ The above reaction is found to be of first order. |
What is the unit of rate constant for the reaction given in the passage |
$mol\, L^{-1}\, s^{-1}$ $mol^{-1}\, L\, s^{-1}$ $s^{-1}$ $mol\, L^{-1}\, s$ |
$s^{-1}$ |
The correct answer is Option (3) → $s^{-1}$ The units for a rate constant ($k$) depend on the overall order of the reaction. The general formula for the units of $k$ is: $\text{Unit of } k = (\text{mol L}^{-1})^{1-n} \text{ s}^{-1}$ Where $n$ is the order of the reaction. Calculation for the Given Reaction Since the passage states the decomposition of $N_2O_5$ is a first-order reaction ($n = 1$): Substitute $n = 1$ into the formula: $\text{Unit of } k = (\text{mol L}^{-1})^{1-1} \text{ s}^{-1}$ Simplify the exponent: $\text{Unit of } k = (\text{mol L}^{-1})^0 \text{ s}^{-1}$ Any value raised to the power of zero is $1$: $\text{Unit of } k = 1 \times \text{s}^{-1} = \text{s}^{-1}$ |