Find the points of local maxima, local minima and the points of inflection of the function $f(x) = x^5 - 5x^4 + 5x^3 - 1$. Also, find the corresponding local maximum and local minimum values. |
Max at $x=0$, Min at $x=3$ Max at $x=1$ (val 0), Min at $x=3$ (val -28) Max at $x=3$ (val -28), Min at $x=1$ (val 0) Max at $x=1$ (val 5), Min at $x=3$ (val -20) |
Max at $x=1$ (val 0), Min at $x=3$ (val -28) |
The correct answer is Option (2) → Max at $x=1$ (val 0), Min at $x=3$ (val -28) ## Given that, $f(x) = x^5 - 5x^4 + 5x^3 - 1$ On differentiating w.r.t. $x$, we get $f'(x) = 5x^4 - 20x^3 + 15x^2$ For maxima or minima, $f'(x) = 0$ $\Rightarrow 5x^4 - 20x^3 + 15x^2 = 0$ $\Rightarrow 5x^2(x^2 - 4x + 3) = 0$ $\Rightarrow 5x^2(x^2 - 3x - x + 3) = 0$ $\Rightarrow 5x^2[x(x - 3) - 1(x - 3)] = 0$ $\Rightarrow 5x^2[(x - 1)(x - 3)] = 0$ $∴x = 0, 1, 3$ Sign scheme for $\frac{dy}{dx} = 5x^2(x - 1)(x - 3)$ So, $y$ has maximum value at $x = 1$ and minimum value at $x = 3$. At $x = 0, y$ has neither maximum nor minimum value. $∴$ Maximum value of $y = 1 - 5 + 5 - 1 = 0$ and minimum value $= (3)^5 - 5(3)^4 + 5(3)^3 - 1$ $= 243 - 81 \times 5 + 27 \times 5 - 1$ $= -28$ |