Consider two independent events A and B such that P(A) = 0.3, P(B) = 0.6.

Match List-I with List-II

Choose the correct answer from the options given below.

(A)-(II), (B)-(III), (C)-(IV), (D)-(I)

The correct answer is Option (3) → (A)-(II), (B)-(III), (C)-(IV), (D)-(I) **

Given: $P(A)=0.3,\ P(B)=0.6$, and A, B are independent.

(A) $P(A\text{ and }B)=P(A)P(B)=0.3\times0.6=0.18$ → (II)

(B) $P(A\text{ and not }B)=P(A)P(B')=0.3\times(1-0.6)=0.3\times0.4=0.12$ → (III)

(C) $P(A\text{ or }B)=P(A)+P(B)-P(A)P(B)=0.3+0.6-0.18=0.72$ → (IV)

(D) $P(\text{neither A nor B})=1-P(A\text{ or }B)=1-0.72=0.28$ → (I)

Matching:

(A) → (II), (B) → (III), (C) → (IV), (D) → (I)