Practicing Success
If $5^x=6^y=30^7$, then what is the value of $\frac{1}{x}+\frac{1}{y}$? |
7 $\frac{1}{7}$ 15 $\frac{1}{18}$ |
$\frac{1}{7}$ |
$5^x=6^y=30^7$ $5^x=30^7$ ⇒ 5^(x*1/x) =30^(7*1/x) ⇒ 5 =30^(7*1/x) $6^y=30^7$ .......(1) ⇒ 6^(y*1/y) =30^(7*1/y) ⇒ 6 =30^(7*1/y) ............(2) Multiply 1 and 2, 30 = (30^7*1/x) (30^7*1/y) = 30^7(1/x + 1/y) ⇒ 7(\(\frac{1}{x}\) + \(\frac{1}{y}\)) = 1 (\(\frac{1}{x}\) + \(\frac{1}{y}\)) = $\frac{1}{7}$ The correct answer is Option (2) → $\frac{1}{7}$ |