A random variable 'X' denotes the number of sixes obtained in three throws of a die, then, the mean of the distribution is:-
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → \(\displaystyle\frac{1}{2}\)
Each throw is an independent trial with P(six) \(= \frac{1}{6}\). So X, the number of sixes in 3 throws, follows the binomial distribution with
\( \displaystyle n = 3,\quad p = \frac{1}{6} \)
The mean of a binomial distribution is np:
\( \displaystyle \text{Mean} = np = 3 \times \frac{1}{6} = \frac{1}{2} \)