Practicing Success
Practicing Success
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If $f(x)=x \tan ^{-1} x$, then f'(1) is equal to |
$\frac{1}{2}+\frac{\pi}{4}$ $-\frac{1}{2}+\frac{\pi}{4}$ $-\frac{1}{2}-\frac{\pi}{4}$ $\frac{1}{2}-\frac{\pi}{4}$ |
$\frac{1}{2}+\frac{\pi}{4}$ |
We have, $f(x)=x \tan ^{-1} x$ $\Rightarrow f'(x)=\tan ^{-1} x+\frac{x}{1+x^2}$ $\Rightarrow f'(1)=\tan ^{-1} 1+\frac{1}{2}=\frac{\pi}{4}+\frac{1}{2}$ |
