Solution of $\frac{dy}{dx}+ y = 2 $ is :

log (2-y) =C-x ; Where C is arbitrary constant of integration logy =Cx; Where C is arbitrary constant of integratin log x= y+1 log(2+y)=C+x; Where C is arbitrary constant of integration

log (2-y) =C-x ; Where C is arbitrary constant of integration

The correct answer is Option (1) → $\log (2-y) =C-x$; Where C is arbitrary constant of integration $\frac{dy}{dx}+ y = 2⇒\frac{dy}{dx}=(2-y)$ so $∫\frac{1}{2-y}dy=∫dx$ $-\log(2-y)=x-C$ $\log(2-y)=C-x$