Solution of dy/dx+ y = 2 is :

The correct answer is Option (1) → $\log (2-y) =C-x$; Where C is arbitrary constant of integration

$\frac{dy}{dx}+ y = 2⇒\frac{dy}{dx}=(2-y)$

so $∫\frac{1}{2-y}dy=∫dx$

$-\log(2-y)=x-C$

$\log(2-y)=C-x$