Find at what time between 10 to 11 o'clock will the hands of a clock be in the same straight line but not together.

10 : 21\(\frac{9}{11}\)

Use this formula for this type of question: (5n - 30)× \(\frac{12}{11}\),

where n is the minimum value of time which is given in the question.

Here, n = 10

Therefore, The hand will be in straight line but not together after = (5 × 10 - 30) × \(\frac{12}{11}\) = 20 × \(\frac{12}{11}\) = × \(\frac{240}{11}\) = 21\(\frac{9}{11}\) min

The hand will be in straight line but not together at = 10 : 21\(\frac{9}{11}\)