Practicing Success
In the given figure, if PQ = 10 cm and PR = 8 cm, then the value of \(\cos {θ}\ + cot {θ}\) = ? |
\(\frac{27}{20}\) cm \(\frac{45}{40}\) cm \(\frac{27}{21}\) cm \(\frac{20}{27}\) cm |
\(\frac{27}{20}\) cm |
Use triplets:- 6, 8, 10 ⇒ QR = 6 cm \(\cos {θ}\ + cot {θ}\) = \(\frac{6}{10}\) cm + \(\frac{6}{8}\) cm = \(\frac{24 + 30}{40}\) cm = \(\frac{54}{40}\) cm = \(\frac{27}{20}\) cm |