Let 0 < P(A) < 1, 0 < P(B) < 1 and P(A ∪ B) = P(A) + P(B) - P(A)P(B). Then:
Answer & explanation
Correct answer: option 4
P(A ∪ B) = P(A) + P(B) - P(A).P(B)
⇒ P(A ∩ B) = P(A).P(B)
$⇒P(A/B)=\frac{P(A ∩ B)}{P(B)}= P(A)$
Let 0 < P(A) < 1, 0 < P(B) < 1 and P(A ∪ B) = P(A) + P(B) - P(A)P(B). Then:
Correct answer: option 4
P(A ∪ B) = P(A) + P(B) - P(A).P(B)
⇒ P(A ∩ B) = P(A).P(B)
$⇒P(A/B)=\frac{P(A ∩ B)}{P(B)}= P(A)$