If tan2x = cot(60°+3x) find the value of sin10x.

1 0 \(\frac{\sqrt {3}}{2}\)  \(\frac{3}{2}\)

\(\frac{\sqrt {3}}{2}\)

If tan 2x = cot(60°+3x) (2x + 60° + 3x)=90° 5x = 30° x = 6° Now, sin 10x=sin10 × 6° sin60° = \(\frac{\sqrt {3}}{2}\)