Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Electrostatic Potential and Capacitance

Question:

Options:

0.75J

0.6 J

0.075 J

0.06 J

Correct Answer:

0.075 J

Explanation:

$ W = \frac{q_1q_2}{4\pi\epsilon_0}(\frac{1}{r_f} - \frac{1}{r_i}) =9\times 10^9 \times 2\times 10^{-6}\times 10\times 10^{-6}(\frac{1}{0.6} - \frac{1}{0.8}) = 0.075J$