The point on the curve $y=-x^2+12x+5$ where the tangent is parallel to the x-axis is :
Answer & explanation
Correct answer: option 2
The correct answer is option (2) → (6, 41)
$y=-x^2+12x+5$ ...(I)
$\frac{dy}{dx}=-2x+12$
tangent parallel to x-axis
$⇒\frac{dy}{dx}=0⇒x=6$
from (I) $y=-(6)^2+12(6)+5$
$=-36+72+5=41$
P(6, 41) at which tangent parallel to x-axis