The 10th term of the A.P. 1, 5, 9, 13, . . ., is:
Answer & explanation
Correct answer: option 4
We have,
5 , 9 , 13…..
a = First Term = 5
d = Common difference = 9 - 5 = 13 - 9 = 4
a = 5 , d = 4
nth term of an AP = a + (n-1)d
10th term of AP = 5 + (10-1) × 4
= 5 + 9 × 4 = 5 + 36 = 41