The 10th term of the A.P. 5, 9, 13, . . ., is:

36 33 37 41

41

We have, 5 , 9 , 13….. a = First Term = 5 d = Common difference = 9 - 5 = 13 - 9 = 4 a = 5 , d = 4 nth term of an AP = a + (n-1)d 10th term of AP = 5 + (10-1) × 4 = 5 + 9 × 4 = 5 + 36 = 41