Geometry of $[Ni(CN)_4]^{2-}$ and $[NiCl_4]^{2-}$ are.............

Square planar, low spin and tetrahedral, high spin respectively

The correct answer is Option (3) → Square planar, low spin and tetrahedral, high spin respectively

• Ni²⁺ = d⁸ configuration
• [Ni(CN)₄]^2-
• CN⁻ is a strong field ligand
• Causes pairing of electrons
• Leads to square planar geometry (dsp²)
• Hence low spin
• [NiCl₄]^2-
• Cl⁻ is a weak field ligand
• No pairing of electrons
• Forms tetrahedral geometry (sp³)
• Hence high spin

So the correct option is: Square planar, low spin and tetrahedral, high spin respectively