Geometry of $[Ni(CN)_4]^{2-}$ and $[NiCl_4]^{2-}$ are.............
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → Square planar, low spin and tetrahedral, high spin respectively
- Ni2+ = d8 configuration
- [Ni(CN)4]2-
- CN⁻ is a strong field ligand
- Causes pairing of electrons
- Leads to square planar geometry (dsp²)
- Hence low spin
- [NiCl4]2-
- Cl⁻ is a weak field ligand
- No pairing of electrons
- Forms tetrahedral geometry (sp³)
- Hence high spin
So the correct option is: Square planar, low spin and tetrahedral, high spin respectively