Practicing Success
Practicing Success
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$\text{Force due to +q_2 on -q_1} = \frac{kq_1q_2}{b^2} \text{along +x direction}$ $\text{X component of force on -q_1 due to -q_3} = \frac{kq_1q_3 sin\theta}{a^2}\text{along + x direction}$ $\text{X component of force} \propto \frac{q_2}{b^2} + \frac{q_3 sin\theta}{a^2}$
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