Find the area of the sector of a circle of radius 7 cm with a central angle of 90°.
Answer & explanation
Correct answer: option 1
We know that ,
Area of sector of circle = π × r² × \(\frac{ θ }{360º}\)
According to question ,
θ = 90º and r = 7 cm
Area of sector of circle = π × 7² × \(\frac{ 90º }{360º}\)
= \(\frac{22}{7}\) × 7² × \(\frac{ 1 }{4}\)
= 22 × 7 × \(\frac{ 1 }{4}\)
= 38.5 cm²