Find the area of the sector of a circle of radius 7 cm with a central angle of 90°.

38.50 cm2 35 cm2 20.67 cm2 28 cm2

38.50 cm2

We know that , Area of sector of circle = π × r² × \(\frac{ θ }{360º}\) According to question , θ = 90º and r = 7 cm Area of sector of circle = π × 7² × \(\frac{ 90º }{360º}\) = \(\frac{22}{7}\) × 7² × \(\frac{ 1 }{4}\) = 22 × 7 × \(\frac{ 1 }{4}\) = 38.5 cm²