If $y=\log \left[\frac{x^2}{e^2}\right]$ then value of $\frac{d^2 y}{d x^2}$ is:
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) - $\frac{-2}{x^2}$
$y=\log\frac{x^2}{e^2}=\log x^2-\log e^2$
$y=2\log x-2×1$
$\frac{dy}{dx}=\frac{z}{x}⇒\frac{d^2y}{dx^2}=\frac{-2}{x^2}$