Practicing Success
If $y=\log \left[\frac{x^2}{e^2}\right]$ then value of $\frac{d^2 y}{d x^2}$ is: |
$\frac{x^2}{e^4}$ $\frac{-2}{x^2}$ $\frac{e}{x^2}$ $2 x+\log 2$ |
$\frac{-2}{x^2}$ |
The correct answer is Option (2) - $\frac{-2}{x^2}$ $y=\log\frac{x^2}{e^2}=\log x^2-\log e^2$ $y=2\log x-2×1$ $\frac{dy}{dx}=\frac{z}{x}⇒\frac{d^2y}{dx^2}=\frac{-2}{x^2}$ |