Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Alternating Current

Question:

Options:

a

b

c

d

Correct Answer:

b

Explanation:

In series RC circuit, the current leads the voltage by an angle in between 0 and 900.

In series RL circuit, the current lags the voltage by an angle in between 0 and 900.

$ \text{phase angle in case 1 is } tan \phi_1 = \frac{X_C}{R} = \frac{1}{\omega CR} = \frac{1000}{\sqrt 3} , \Rightarrow \phi_1 =  90^0$ 

$  \text{phase angle in case 1 is } tan \phi_2 = \frac{X_L}{R} = \frac{\omega L}{R} = \sqrt 3 , \Rightarrow \phi_2 = 60^0$

$\text{phase difference } = 90^0 + 60^0 =150^0$