Practicing Success
Four massive particles, each of mass m, are kept at the vertices of square of side $\ell$. With what speed should each particle be projected so as to stabilise the system ? |
$\sqrt{\frac{Gm}{\ell}\left(1+\frac{1}{4 \sqrt{2}}\right)}$ $\sqrt{\frac{Gm}{\ell}\left(1+\frac{1}{2 \sqrt{2}}\right)}$ $\sqrt{\frac{Gm}{2 \ell}\left(1+\frac{1}{2 \sqrt{2}}\right)}$ $\sqrt{\frac{Gm}{\ell}\left(1+\frac{1}{\sqrt{2}}\right)}$ |
$\sqrt{\frac{Gm}{\ell}\left(1+\frac{1}{2 \sqrt{2}}\right)}$ |
In order to stabilise the system, each mass should move in a circular path of the same radius about the centre of the square. How is it possible? It is possible when each particle moves perpendicular to the corresponding diagonal with a speed, let v. As a result the net gravitational force on the particle due to the others will provide necessary centripetal acceleration v2/r, where r = $\ell / \sqrt{2}$. $\Rightarrow F_g=m \frac{v^2}{r}=\frac{m v^2}{\left(\frac{\ell}{\sqrt{2}}\right)}$ .....(1) where Fg = Net gravitational force on each particle. Resolving the individual gravitational force along the diameter, we obtain, $F_g=\frac{F}{\sqrt{2}}+\frac{F}{\sqrt{2}}+F'=F'+\sqrt{2} F$ Putting $F = \frac{G m^2}{\ell^2}$ and $F'=\frac{G m^2}{2 \ell^2}$ $\Rightarrow F_g=\frac{G m^2}{\ell^2}\left(\sqrt{2}+\frac{1}{2}\right)$ ......(2) Using (1) and (2), we obtain, $v=\sqrt{\frac{G m}{\ell}\left(1+\frac{1}{2 \sqrt{2}}\right)}$ |