If 5 cos θ = 4 sin θ, 0° ≤ θ ≤ 90°, then what will be the value of se…

5 cos θ = 4 sin θ

cot θ = \(\frac{4}{5}\) 

{ cot θ = \(\frac{B}{P}\) }

By using pythagoras theorem,

P² + B² = H²

5² + 4² = H²

H = √41

Now,

secθ 

= \(\frac{H}{B}\)

= \(\frac{√41 }{4}\)