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CUET
Physics
Nuclei
When ${^{232}_{92}Th}$ changes into ${^{208}_{82}Pb}$, the number of $α$ and $β^-$ particles emitted are
$α = 6;β=6$
$α = 6;β=4$
$α = 4;β=6$
$α = 6;β=2$
The correct answer is Option (4) → $α = 6;β=2$