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A proton moving with a velocity of (6i+8j) ×105 ms−1 enters uniform magnetic field of induction 5×10−3k T. What is the magnitude of the force acting on the proton? |
0 8×10−16N 3×10−16N 4×10−16N |
8×10−16N |
Force on a charged particle in magnetic field : F = q (v × B)
q : 1.6 x 10-19 C ; v = (6i + 8j) x 105 m s-1 ; B = 5×10−3k T
|F| = 8 x 10-17 N |
