If A and B are two events, the probability that exactly one of them occurs is given by
Answer & explanation
Correct answer: option 1
$P(A \bar{B} \cup \bar{A} B)=P(A)-P(A B)+P(B)-P(A B)$
$=P(A)+P(B)-2 P(A B)$
If A and B are two events, the probability that exactly one of them occurs is given by
Correct answer: option 1
$P(A \bar{B} \cup \bar{A} B)=P(A)-P(A B)+P(B)-P(A B)$
$=P(A)+P(B)-2 P(A B)$