CUET Preparation Today
If A and B are two events, the probability that exactly one of them occurs is given by |
$P(A)+P(B)-2 P(A \cap B)$ $P\left(A \cap B'\right)-P\left(A' \cap B\right)$ $P(A \cup B)+P(A \cap B)$ $P\left(A'\right)+P\left(B'\right)+2 P\left(A' \cap B'\right)$ |
$P(A)+P(B)-2 P(A \cap B)$ |
$P(A \bar{B} \cup \bar{A} B)=P(A)-P(A B)+P(B)-P(A B)$ $=P(A)+P(B)-2 P(A B)$ |
