In a certain region, a uniform electric field exists in the positive x-direction. Let $V_A$ = electric potential at point (0, 0, 0) cm, $V_B$ = electric potential at point (5, 0, 0) cm and $V_C$ = electric potential at point (0, 5, 0) cm. The correct relationship between them is

$V_A = V_C$ and $V_A > V_B$

The correct answer is Option (2) → $V_A = V_C$ and $V_A > V_B$

For a uniform electric field $\vec{E}$ in the positive x-direction, the potential difference depends only on the x-coordinate:

$V_B - V_A = - \vec{E} \cdot \vec{AB} = - E \cdot (5 - 0) = -5E$

Along the y-direction, there is no change in x, so potential remains the same:

$V_C - V_A = - \vec{E} \cdot \vec{AC} = 0$

Therefore:

$V_A = V_C > V_B$

Final Answer: $V_A = V_C > V_B$