Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Matrices

Question:

Let p be a non-singular matrix, and $I +p+p^2+...+p^n = O$. Then find $p^{-1}$.

Options:

$-p$

$p$

$p^n$

none of these

Correct Answer:

$p^n$

Explanation:

We have, $I +p+p^2+...+p^n = O$   ...(1)

Since p is non-singular matrix, p is invertible.

Multiplying both sides of (1) by $p^{-1}$, we get

$⇒p^{-1}I + p^{-1}p + p^{-1}p^2 + ... + p^{-1}p^n= p^{-1}O$

$⇒p^{-1}+I+p+p^2+...+p^{n-1}=O$

$⇒p^{-1}=-(I+p+ p^2+...+p^{n-1})$

$⇒p^{-1}=-(-p^n) =p^n$