Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Units and Measurements

Question:

The frequency (n) of vibration of a string is given as n = \(\frac{1}{2l}\sqrt{\frac{T}{m}}\), where T is tension and l is the length of vibrating string, then the dimensional formula of m is : 

Options:

[M0L1T1]

[M0L0T0]

[M1L-1T0]

[M1L0T0]

Correct Answer:

[M1L-1T0]

Explanation:

n = \(\frac{1}{2l}\sqrt{\frac{T}{m}}\)

n2 = \(\frac{1}{4l^2}\frac{T}{m}\)

m = \(\frac{1}{4l^2}\frac{T}{n^2}\)

m = [\(\frac{MLT^{-2}}{L^2 T^{-2}}\)]

m = [ML-1]