Find the total current drawn from the battery as shown in the circuit diagram :

0.33 A 0.66 A 3.3 A 13.3 A

0.33 A

This circuit is balanced wheat stone bridge. Hence $50\Omega$ resistors can be removed from the circuit. 3 , $10\Omega$ resistor are in series . Two $30\Omega$ resistor are in parallel. Equivalent resistance is $15\Omega$.  $ I = \frac{6}{3+15} =\frac{1}{3} = 0.33A$