Given two independent events A and B such that P(A) = 0.3 and P(B) = 0.6, then
Match the following
|
LIST I |
LIST II |
|
A. P(A and B) |
I. 0.28 |
|
B. P(A and not B) |
II. 0.72 |
|
C. P(A or B) |
III. 0.12 |
|
D. P(neither A nor B) |
IV. 0.18 |
Choose the correct answer from the options given below:
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → A - IV, B - III, C - II, D - I
(A) $P(A∩B)=P(A)P(B)=0.18$ (IV)
(B) $P(A∩\bar B)=P(A)P(\bar B)=0.3×0.4=0.12$ (III)
(C) $P(A\,or\,B)=P(A)+P(B)-P(A∩B)=0.3+06-0.18=0.72$ (II)
(D) $P(\bar A∩\bar B)=P(\overline{A∪B})=1-P(A∪B)=1-0.72=0.28$ (I)