Given two independent events A and B such that P(A) = 0.3 and P(B) = 0.6, then

Match the following

Choose the correct answer from the options given below:

A - IV, B - III, C - II, D - I

The correct answer is Option (1) → A - IV, B - III, C - II, D - I

(A) $P(A∩B)=P(A)P(B)=0.18$ (IV)

(B) $P(A∩\bar B)=P(A)P(\bar B)=0.3×0.4=0.12$ (III)

(C) $P(A\,or\,B)=P(A)+P(B)-P(A∩B)=0.3+06-0.18=0.72$ (II)

(D) $P(\bar A∩\bar B)=P(\overline{A∪B})=1-P(A∪B)=1-0.72=0.28$ (I)