In triangle ABC, B = 90°, and C = 45°. If AC = 2$\sqrt{2}$ cm, then the length of BC is:
Answer & explanation
Correct answer: option 2
cos\({45}^\circ\) = \(\frac{BC}{2√2}\)
BC = \(\frac{2√2}{√2}\) = 2 cm.
Therefore, BC = 2 cm.
In triangle ABC, B = 90°, and C = 45°. If AC = 2$\sqrt{2}$ cm, then the length of BC is:
Correct answer: option 2
cos\({45}^\circ\) = \(\frac{BC}{2√2}\)
BC = \(\frac{2√2}{√2}\) = 2 cm.
Therefore, BC = 2 cm.