Arrange the following complexes in increasing order of conductivity of their solution:
(A) $[Co(NH_3)_3Cl_3]$
(B) $[Co(NH_3)_4Cl_2]Cl$
(C) $[Co(NH_3)_6]Cl_3$
(D) $[Co(NH_3)_5Cl]Cl_2$
Choose the correct answer from the options given below:
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → (A), (B), (D), (C)
Conductivity of a solution increases with the number of ions produced on dissociation.
- (A) [Co(NH₃)₃Cl₃]
→ Neutral complex, no ionisation
→ Least conductivity - (B) [Co(NH₃)₄Cl₂]Cl
→ Dissociates into:
$[Co(NH₃)₄Cl₂]^+ + Cl^-$ → 2 ions - (D) [Co(NH₃)₅Cl]Cl₂
→ Dissociates into:
$[Co(NH₃)₅Cl]^{2+} + 2Cl^-$ → 3 ions - (C) [Co(NH₃)₆]Cl₃
→ Dissociates into:
$[Co(NH₃)₆]^{3+} + 3Cl^-$ → 4 ions
→ Highest conductivity
Increasing order of conductivity: $(A) < (B) < (D) < (C)$
Hence, the correct option is (A), (B), (D), (C)