The direction cosines of a line which makes equal angles with co-ordinate axes are: |
$±\left(\frac{1}{\sqrt{3}},\frac{1}{\sqrt{3}},\frac{1}{\sqrt{3}}\right)$ $±(1, 1, 1)$ $±\left(\frac{1}{3},\frac{1}{3},\frac{1}{3}\right)$ $±\left(\frac{1}{\sqrt{3}},\frac{-1}{\sqrt{3}},\frac{-1}{\sqrt{3}}\right)$ |
$±\left(\frac{1}{\sqrt{3}},\frac{1}{\sqrt{3}},\frac{1}{\sqrt{3}}\right)$ |
The correct answer is Option (1) → $±\left(\frac{1}{\sqrt{3}},\frac{1}{\sqrt{3}},\frac{1}{\sqrt{3}}\right)$ For a line making equal angles with all coordinate axes: Let the direction cosines be $(l, m, n)$. Since it makes equal angles, $l = m = n$. Using $l^2 + m^2 + n^2 = 1$: $3l^2 = 1 \Rightarrow l = \pm \frac{1}{\sqrt{3}}$ Hence direction cosines: $\left(\pm \frac{1}{\sqrt{3}}, \pm \frac{1}{\sqrt{3}}, \pm \frac{1}{\sqrt{3}}\right)$ Correct answer: $\pm\left(\frac{1}{\sqrt{3}}, \frac{1}{\sqrt{3}}, \frac{1}{\sqrt{3}}\right)$ |