If 2a2 + 3b2 - 8a + 24b + 56 = 0 find \(\frac{{b}^{2}}{a}\)

1 2 3 8

8

If 2a2 + 3b2 = 2(4a - 12b) - 56  [Moving a2 + b2 + c2 = 2(ab + bc + ca) form] Here the value of a = \(\frac{Cofficient of a}{Cofficient of{a}^{2}}\) a = \(\frac{4}{2}\) = 2 Value of b = \(\frac{Cofficient of b}{Cofficient of{b}^{2}}\) b = \(\frac{-12}{3}\) = -4 Put in find → \(\frac{({-4})^{2}}{2}\) = 8