If 2a2 + 3b2 - 8a + 24b + 56 = 0
find \(\frac{{b}^{2}}{a}\)
Answer & explanation
Correct answer: option 4
If 2a2 + 3b2 = 2(4a - 12b) - 56 [Moving a2 + b2 + c2 = 2(ab + bc + ca) form]
Here the value of a = \(\frac{Cofficient of a}{Cofficient of{a}^{2}}\)
a = \(\frac{4}{2}\) = 2
Value of b = \(\frac{Cofficient of b}{Cofficient of{b}^{2}}\)
b = \(\frac{-12}{3}\) = -4
Put in find → \(\frac{({-4})^{2}}{2}\) = 8