The symmetrical form of the line of intersection of the planes $ x = ay +b, z=cy + d, $ is
Answer & explanation
Correct answer: option 2
$x = ay + b,\quad z = cy + d$
$y = \lambda$
$x = a\lambda + b,\quad z = c\lambda + d$
$\text{Direction ratios} = (a, 1, c)$
$\text{Point on line} = (b, 0, d)$
$\frac{x - b}{a} = \frac{y - 0}{1} = \frac{z - d}{c}$
The symmetric form is $\frac{x - b}{a} = \frac{y}{1} = \frac{z - d}{c}$.