Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Atoms

Question:

The ratio of minimum to maximum wavelength in Balmer series is

Options:

5 : 9

5 : 36

1 : 4

3 : 4

Correct Answer:

5 : 9

Explanation:

$\frac{1}{\lambda}=R\left[\frac{1}{n_1^2}-\frac{1}{n_2^2}\right] \Rightarrow \frac{\lambda_{\min }}{\lambda_{\max }}=\frac{\left[\frac{1}{2^2}-\frac{1}{3^2}\right]}{\left[\frac{1}{2^2}-\frac{1}{\infty}\right]}=\frac{5}{9}$