$\int e^x\left(\frac{2 x+1}{2 \sqrt{x}}\right) d x=$
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → $e^x \sqrt{x}+C$
$\int e^x\left(\frac{2 x+1}{2 \sqrt{x}}\right) d x$
$=\int e^x\left(\sqrt{x}+\frac{1}{2\sqrt{x}}\right) d x$
$f(x)=\sqrt{x},f(x)=\frac{1}{2\sqrt{x}}$
$=e^x\sqrt{x}+C$