A 2-ton vehicle travels at 20m/s on a road where the frictional force is 10% of the weight of the vehicle. What is the power required? (Assume g = 10m/s²)

440 kW

Weight of car = m x g

    = 2000 x 10 = 20000 N

Frictional force = \(\frac{10}{100}\) x (20000)

    = 2000 N

Total force (F) = 20000 + 2000 = 22000 N

Velocity (v) = 20 m/s

P = F x v

= 22000 x 20

= 440000 W = 440 kW.